X^2+4.1x+2.5=0

Solution for X^2+4.1x+2.5=0 equation:

X^2+4.1X+2.5=0

a = 1; b = 4.1; c = +2.5;
Δ = b2-4ac
Δ = 4.12-4·1·2.5
Δ = 6.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.1)-\sqrt{6.81}}{2*1}=\frac{-4.1-\sqrt{6.81}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.1)+\sqrt{6.81}}{2*1}=\frac{-4.1+\sqrt{6.81}}{2}
$